I got lotion in my eye
Ya ake cin gindin mata
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And, New Kinetic Energy = KE f = 1/2 m f v f = 1/2 m f x 2m i v i /m f = 1/2 x m f /m f x m i v i = m i v i Thus, the kinetic energy changes by a factor of 2 or becomes doubled. Also Note that m i = m f = m as mass doesn't change in this case. The kinetic energy of a body because four times its initial value ..The new linear momentum will be . Books. Physics. If momentum is doubled by doubling the mass while retaining the same velocity, the Kinetic energy is doubled, or a 100 % increase. If the mass remains the same, but the velocity is doubled, the kinetic energy increases by a factor of 4 or a 300% increase.
E) both kinetic energy and momentum are conserved. Ans: E Section: 8–2 Topic: Kinetic Energy of a System Type: Conceptual 15 If a body moves in such a way that its linear momentum is constant, then A) its kinetic energy is zero. B) the sum of all the forces acting on it must be zero. The kinetic energy of a body because four times its initial value ..The new linear momentum will be . Books. Physics.
K.E is kinetic energy . m is mass of body . v is velocity ===== And formula for linear momentum is :-Put value of v in (1) We, get. =====> Now solving it . But, here 2m is constant. then , ∴ If kinetic energy is doubled then liner momentum will also increase twice.
See full list on courses.lumenlearning.com It depends how you increased the KE. If you increased it by increasing the mass, then the momentum would go up in direct proportion to the KE. If you increased it by increasing the velocity, then the momentum would increase by the square root of the KE increase (due to KE being proportional to velocity squared, while momentum is proportional to velocity).
If the kinetic energy of a body is increased by 4% the momentum: (1)increases by 2% (2)increases by 4% (3)increases by 8% (4)increases by 16% Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day. If momentum is doubled, the percent increment of kinetic energy will depend on the ratio of the mass of the first case over the mass in the second case, m1/m2.